Solution 1: accepted 1ms
DFS.
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Simplified 0ms12345public int maxDepth(TreeNode root) { if (root == null) return 0; return Math.max(maxDepth(root.left), maxDepth(root.right)) + 1;}
DFS.
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Simplified 0ms12345public int maxDepth(TreeNode root) { if (root == null) return 0; return Math.max(maxDepth(root.left), maxDepth(root.right)) + 1;}